Throughout Season 7 of the show, both of these characters have undergone a lot of individual growth, with Tim working on his ...

ABC's 'The Rookie' is in production for season 8, and showrunner Alexi Hawley spoke about Chenford getting back together when ...

The Rookie star Nathan Fillion and showrunner Alexi Hawley have given a much-anticipated update on Chenford's status in The ...

The Rookie may not be returning until midseason, but one star is hyping fans up for Season 8. Eric Winter shared a behind-the ...

Below, showrunner Alexi Hawley (who guest stars as the documentary’s interviewer) talks about that key moment for Chenford and what’s ahead — and the storyline that could come back in Season 8.

The Rookie Season 7 airs on Tuesdays at 9:00 pm ET. The post The Rookie Showrunner on if Chenford Will Get Back Together appeared first on ComingSoon.net - Movie Trailers, TV & Streaming News, and ...

And while none of the Chenford issues can be blamed on the time jump of six weeks, I can't help but suspect that the jump is going to cause some problems for watching The Rookie.

‘The Rookie’ Creator Explains Why Those #Chenford Finale Scenes Are an ‘Important Step for the Future’ The fan-favorite duo’s tender elevator moment shows Tim “understands that he’s ...

Spoilers ahead for Season 6, Episode 6 of The Rookie, “Secrets and Lies.” The latest episode of The Rookie brought some heartbreak for Chenford and fans of the relationship.

Chenford is really happening! The couple that shippers have been rooting for since The Rookie Season 1 is finally planning on going on a date! Oh, and the winter finale had some other things, too ...

Chenford might be a bit spicier than some of the other couples on The Rookie, but when it comes to solid partnerships, there's no one better than Wesley Evers (Shawn Ashmore) and Angela Lopez ...

The Rookie ‘s Twitter page released a clip of Eric Winter, who plays Tim, sharing his thoughts on where Chenford is headed in season 5. “Wow. What do I think is next for Chenford?” Winter said.